例如：
id?????????? name???????? value
1?????????????? a???????????????? pp
2?????????????? a???????????????? pp
3?????????????? b???????????????? iii
4?????????????? b???????????????? pp
5?????????????? b???????????????? pp
6?????????????? c???????????????? pp
7?????????????? c???????????????? pp
8?????????????? c???????????????? iii
id是主鍵
要求得到這樣的結(jié)果
id?????????? name???????? value
1?????????????? a???????????????? pp
3?????????????? b???????????????? iii
4?????????????? b???????????????? pp
6?????????????? c???????????????? pp
8?????????????? c???????????????? iii

方法1
delete?? YourTable??
where?? [id]?? not?? in?? (
select?? max([id])?? from?? YourTable??
group?? by?? (name?? +?? value))

方法2
delete?? a
from?? 表?? a?? left?? join(
select?? id=min(id)?? from?? 表?? group?? by?? name,value
)b?? on?? a.id=b.id
where?? b.id?? is?? null



查詢(xún)及刪除重復(fù)記錄的SQL語(yǔ)句
查詢(xún)及刪除重復(fù)記錄的SQL語(yǔ)句
1、查找表中多余的重復(fù)記錄，重復(fù)記錄是根據(jù)單個(gè)字段（peopleId）來(lái)判斷
select * from people
where peopleId in (select?? peopleId from?? people group by?? peopleId having count(peopleId) > 1)
2、刪除表中多余的重復(fù)記錄，重復(fù)記錄是根據(jù)單個(gè)字段（peopleId）來(lái)判斷，只留有rowid最小的記錄
delete from people
where peopleId in (select?? peopleId from people group by?? peopleId?? having count(peopleId) > 1)
and rowid not in (select min(rowid) from?? people group by peopleId having count(peopleId )>1)
3、查找表中多余的重復(fù)記錄（多個(gè)字段）
select * from vitae a
where (a.peopleId,a.seq) in?? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4、刪除表中多余的重復(fù)記錄（多個(gè)字段），只留有rowid最小的記錄
delete from vitae a
where (a.peopleId,a.seq) in?? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查找表中多余的重復(fù)記錄（多個(gè)字段），不包含rowid最小的記錄
select * from vitae a
where (a.peopleId,a.seq) in?? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
(二)
比方說(shuō)
在A表中存在一個(gè)字段“name”，
而且不同記錄之間的“name”值有可能會(huì)相同，
現(xiàn)在就是需要查詢(xún)出在該表中的各記錄之間，“name”值存在重復(fù)的項(xiàng)；
Select Name,Count(*) From A Group By Name Having Count(*) > 1
如果還查性別也相同大則如下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

(三)
方法一
declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >； 1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@max
end
close cur_rows
set rowcount 0 方法二
＂重復(fù)記錄＂有兩個(gè)意義上的重復(fù)記錄，一是完全重復(fù)的記錄，也即所有字段均重復(fù)的記錄，二是部分關(guān)鍵字段重復(fù)的記錄，比如Name字段重復(fù)，而其他字段不一定重復(fù)或都重復(fù)可以忽略。
1、對(duì)于第一種重復(fù)，比較容易解決，使用
select distinct * from tableName
就可以得到無(wú)重復(fù)記錄的結(jié)果集。
如果該表需要?jiǎng)h除重復(fù)的記錄（重復(fù)記錄保留1條），可以按以下方法刪除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
發(fā)生這種重復(fù)的原因是表設(shè)計(jì)不周產(chǎn)生的，增加唯一索引列即可解決。
2、這類(lèi)重復(fù)問(wèn)題通常要求保留重復(fù)記錄中的第一條記錄，操作方法如下
假設(shè)有重復(fù)的字段為Name,Address，要求得到這兩個(gè)字段唯一的結(jié)果集
select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)
最后一個(gè)select即得到了Name，Address不重復(fù)的結(jié)果集（但多了一個(gè)autoID字段，實(shí)際寫(xiě)時(shí)可以寫(xiě)在select子句中省去此列）
(四)
查詢(xún)重復(fù)
select * from tablename where id in (
select id from tablename
group by id
having count(id) > 1
)

用SQL刪除重復(fù)記錄的N種方法