Judge Info
- Memory Limit: 32768KB
- Case Time Limit: 10000MS
- Time Limit: 10000MS
- Judger: Normal
Description
An anagram is formed by rearranging the letters of a word. You are given a string, please find out if it is an anagram of a word or not. No word will have have more than 50 characters.
Input
The input will consist of a word on one line. The following line contains a number,?, of strings to be tested.
Output
For each test string, if the test string is identical to the source string, output 'IDENTICAL', if it is an anagram, output 'ANAGRAM' otherwise output 'NOT AN ANAGRAM', in a single line.
Sample Input
cares
5
scare
races
cares
another
acres
Sample Output
ANAGRAM
ANAGRAM
IDENTICAL
NOT AN ANAGRAM
ANAGRAM
?
?
?
解題思路：字符串?dāng)?shù)組排序，但是我的方法并不好，只是勉強(qiáng)解出來而已。不過學(xué)會了使用qsort函數(shù)。
1
#include <stdio.h>
2
#include <
string
.h>
3
char
A[
52
];
4
char
B[
52
];
5
char
C[
52
];
6
7
void
swap(
char
*a,
char
*
b){
8
char
t;
9
t=*
a;
10
*a=*
b;
11
*b=
t;
12
}
13
14
int
main() {
15
scanf(
"
%s
"
,A);
16
int
n,flag,i,j;
17
scanf(
"
%d
"
,&
n);
18
for
(i=
0
;i<strlen(A);++
i){
19
C[i]=
A[i];
20
}
21
while
(n--
) {
22
23
scanf(
"
%s
"
,B);
24
flag=
1
;
25
for
(i=
0
;i<strlen(A);++
i) {
26
if
(A[i]!=
B[i])
27
flag=
0
;
28
}
29
if
(flag==
1
){printf(
"
IDENTICAL\n
"
);
continue
;}
30
for
(i=
0
;i<strlen(C)-
1
;++
i) {
31
for
(j=i+
1
;j<strlen(C);++
j) {
32
if
(B[i]>
B[j])
33
swap(&B[i],&
B[j]);
34
if
(C[i]>
C[j])
35
swap(&C[i],&
C[j]);
36
}
37
}
38
39
for
(i=
0
;i<strlen(A);++
i) {
40
if
(C[i]!=
B[i])
41
flag=
2
;
42
}
43
if
(flag==
0
){printf(
"
ANAGRAM\n
"
);
continue
;}
44
else
printf(
"
NOT AN ANAGRAM\n
"
);
45
}
46
}
大神解法：
1
#include<stdio.h>
2
#include<stdlib.h>
3
#include<
string
.h>
4
5
char
S[
55
];
6
7
int
cmp(
const
void
*a,
const
void
*
b)
8
{
9
return
*(
char
*)a-*(
char
*
)b;
10
}
11
12
int
main()
13
{
14
int
n,i,len1,len2;
15
char
str[
55
],temp[
55
];
16
scanf(
"
%s
"
,S);
17
strcpy(temp,S);
18
len1=
strlen(S);
19
qsort(S,len1,
sizeof
(
char
),cmp);
20
scanf(
"
%d
"
,&
n);
21
for
(i=
0
;i<n;i++
)
22
{
23
memset(str,
0
,
sizeof
(str));
24
scanf(
"
%s
"
,str);
25
len2=
strlen(str);
26
if
(len2!=
len1)
27
{
28
printf(
"
NOT AN ANAGRAM\n
"
);
29
continue
;
30
}
31
if
(
0
==
strcmp(str,temp))
32
{
33
printf(
"
IDENTICAL\n
"
);
34
continue
;
35
}
36
else
37
{
38
qsort(str,len2,
sizeof
(
char
),cmp);
39
if
(
0
==
strcmp(S,str))
40
printf(
"
ANAGRAM\n
"
);
41
else
42
printf(
"
NOT AN ANAGRAM\n
"
);
43
}
44
}
45
return
0
;
46
}
?
?
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